AZING!What is the Polytopic Index for a given set of Pressure and Volume values?

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The discussion focuses on calculating the polytropic index (n) using given pressure (P1, P2) and volume (V1, V2) values. The relationship P1V1^n = P2V2^n is established, leading to the equation ln(P1) - ln(P2) = n(ln(V2) - ln(V1)). The user expresses difficulty in isolating n and considers using logarithmic properties to solve the equation. Assistance is requested to clarify the steps needed to derive n from the provided values. The conversation emphasizes the importance of understanding the logarithmic manipulation to solve for the polytropic index.
tsukuba
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Homework Statement


Hello, I came across a problem where the polytropic index is not given but I've been given P1, P2, V1 and V2.

P1V1 = P2V2 (130kPa)(0.007m3)n = (100kPa)(0.08637m3)n ----> n=1.249

Homework Equations


PVn=constant
I was thinking I would have to use log to figure out n maybe?

The Attempt at a Solution


haven't been able to work it out backwards. Need your help please!
 
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tsukuba said:
I was thinking I would have to use log to figure out n maybe?
If xn = k then ln(xn) = ln(k)AM
 
the value of n is not given. I just put it there because but what if it was
xn = ?
solving for n
 
somebody helpppp
I have a test tomorrow
 
I came to this but now I am not sure how to isolate for n

ln(130) n*ln(0.07) = ln(100) n*ln90.08637)
 
tsukuba said:
I came to this but now I am not sure how to isolate for n

ln(130) n*ln(0.07) = ln(100) n*ln90.08637)

P_1V_1^n = P_2V_2^n
\frac{P_1}{P_2} = \left(\frac{V_2}{V_1}\right)^n
\ln(P_1)-\ln(P_2) = n(\ln(V_2) - \ln(V_1))

Can you work it out from there?

AM
 
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