Balance of forces for two charged spheres hanging from the ceiling

In summary: I think you are trying to say that the masses are the same if the amount of electric charge on each ball is the same.
  • #1
MatinSAR
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Homework Statement
I know that in order for the ropes to have an equal angle as shown in the figure below, the weight of the two balls and the sign of the electric charge must be the same.
But how about the amount of charge?
Relevant Equations
F=kqQ/(r^2)
1676032284207.png

I think if we don't consider electron's/proton's mass then we can say that the amount of charge doesn't need to be equal according to Newton's 3rd Law. I mean having q on one ball and 2q on another ball , still makes the angles having the same size. Is it true ?

What if we consider proton's mass(or electron's mass) ???
I think both balls should have same amount of electric charge and number of protons(electrons)on each ball should be equal.
 
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  • #2
If I understand you, you are concerned about the change in mass resulting from the charge that a ball may be holding.
The givens are that the ropes are at equal angles and there is no other force applied to the balls (for example, between a ball and the ceiling).

If there is no other context to this question, I would explicitly invoke massless electrons - from the same source as the massless ropes commonly used in problems such as these - or from the same source as a ceiling that applies no electrostatic force to the hanging balls.
 
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  • #3
MatinSAR said:
I know that in order for the ropes to have an equal angle as shown in the figure below, the weight of the two balls and the sign of the electric charge must be the same.
Are you sure about the bold part? I certainly agree that the charges must have the same sign but are you sure there is no way to fiddle the mass/charge ratio so that the weights are not the same?
 
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  • #4
MatinSAR said:
Relevant Equations:: F=kqQ/(r^2)

I think if we don't consider electron's/proton's mass ...
I do not see the electron mass or the proton mass in your relevant formula.
But I don't see an expression for each of the two angles either, so I wonder how you can make any statements at all ?
 
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  • #5
MatinSAR said:
Homework Statement:: I know that in order for the ropes to have an equal angle as shown in the figure below, the weight of the two balls and the sign of the electric charge must be the same.
But how about the amount of charge?
Consider two facts that you must already be familiar with.
  1. For the two masses to hang in equilibrium, their center of mass must be below the level of support.
  2. The force that charge A exerts on charge B has the same magnitude and opposite direction to the force that B exerts on A.
Put the two together.
 
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  • #6
.Scott said:
If I understand you, you are concerned about the change in mass resulting from the charge that a ball may be holding.
The givens are that the ropes are at equal angles and there is no other force applied to the balls (for example, between a ball and the ceiling).

If there is no other context to this question, I would explicitly invoke massless electrons - from the same source as the massless ropes commonly used in problems such as these - or from the same source as a ceiling that applies no electrostatic force to the hanging balls.
Good idea. Thank you for your time.
phinds said:
Are you sure about the bold part? I certainly agree that the charges must have the same sign but are you sure there is no way to fiddle the mass/charge ratio so that the weights are not the same?
I think they should have similar mass.
1676046400950.png

BvU said:
I do not see the electron mass or the proton mass in your relevant formula.
But I don't see an expression for each of the two angles either, so I wonder how you can make any statements at all ?
I said the charges should have same sign because otherwise they will get closer.
And I said they should have equal mass because of above image.
I was not sure about the amount of charge on each ball ...
kuruman said:
Consider two facts that you must already be familiar with.
  1. For the two masses to hang in equilibrium, their center of mass must be below the level of support.
  2. The force that charge A exerts on charge B has the same magnitude and opposite direction to the force that B exerts on A.
Put the two together.
Thank you but I haven't read about number one before ...
Can't we find out if amount of electric charge on each ball should be the same or not without fact number 1?
 
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  • #7
MatinSAR said:
I think they should have similar mass.
So, you've moved from identical mass to "similar" mass. Even for that, I have to ask ... why?
 
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  • #8
phinds said:
So, you've moved from identical mass to "similar" mass. Even for that, I have to ask ... why?
What is the difference ???
 
  • #9
MatinSAR said:
What is the difference ???
?? You don't understand the difference between "identical" and "similar"
 
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  • #10
phinds said:
?? You don't understand the difference between "identical" and "similar"
I mean m1=m2 ...
 
  • #11
Hello @MatinSAR. I follow your work shown in green in your figure of post #6. Can you state your reasoning for writing the purple equation ##F \cot \theta = F' \cot \theta##? I think you're probably thinking correctly and you're getting this equation from something you mentioned in your first post. But please confirm how you got the purple equation.

You were also asking whether the two charges had to have the same magnitude. You should be able to answer this by inspecting Coulomb's law.

As @.Scott mentioned, changing the charge of a ball does not change the mass of the ball by any significant amount.
 
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  • #12
MatinSAR said:
I mean m1=m2 ...
Which is not necessary for this problem --- that's what I'm trying to get you to see.
 
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  • #13
TSny said:
I think you're probably thinking correctly and you're getting this equation from something you mentioned in your first post. But please confirm how you got the purple equation.
Hello. Because of Newton's 3rd law F should be equal to F'.
1676059751596.png

TSny said:
You were also asking whether the two charges had to have the same magnitude. You should be able to answer this by inspecting Coulomb's law.
I think it's not necessary because of the fact that F12=F21.
TSny said:
As @.Scott mentioned, changing the charge of a ball does not change the mass of the ball by any significant amount.
So mass of the balls should be the same and the charges should have same sign ...
And it is not necessary to have same amount of charge on each ball.
Is it true?
 
  • #14
phinds said:
Which is not necessary for this problem --- that's what I'm trying to get you to see.
Can you tell me why ?!
Here #6 I have proved that the mass of two balls should be equal.(m1= m2)
 
  • #15
MatinSAR said:
Can you tell me why ?!
Here #6 I have proved that the mass of two balls should be equal.(m1= m2)
No, you did not. You proved that if you assume the charges are identical then the masses have to be identical. That is a vacuous truth. Please THINK about the problem. You clearly did not think through post #3.
 
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  • #16
MatinSAR said:
Hello. Because of Newton's 3rd law F should be equal to F'.
Yes. The 3rd law is the basis for your purple equation.

MatinSAR said:
I think it's not necessary because of the fact that F12=F21.
OK. But, also, the electric force depends on the charges as the product of the charges. So, the electric force will not change if you change the individual charges such that their product remains the same.

MatinSAR said:
So mass of the balls should be the same and the charges should have same sign ...
And it is not necessary to have same amount of charge on each ball.
Is it true?
Yes.
 
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  • #17
phinds said:
No, you did not. You proved that if you assume the charges are identical then the masses have to be identical. That is a vacuous truth. Please THINK about the problem. You clearly did not think through post #3.
Thank you for your help and time. I'll spend more time on it tomorrow morning ... perhaps I will understand what were you trying to tell me ... 🙏
TSny said:
Yes. The 3rd law is the basis for your purple equation.OK. But, also, the electric force depends on the charges as the product of the charges. So, the electric force will not change if you change the individual charges such that their product remains the same.Yes.
I have understand it completely.
Thanks a lot for your time.
 
  • #18
phinds said:
You proved that if you assume the charges are identical then the masses have to be identical.
No, the assumption made in post #6 is that the electrostatic forces are equal and opposite. Seems fair.
 
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  • #19
haruspex said:
No, the assumption made in post #6 is that the electrostatic forces are equal and opposite. Seems fair.
Good point. I was thinking about it incorrectly.
 
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FAQ: Balance of forces for two charged spheres hanging from the ceiling

How do the forces acting on the charged spheres achieve equilibrium?

The forces acting on the charged spheres achieve equilibrium through the balance of three main forces: the gravitational force (weight) acting downward, the tension in the string acting upward and along the string, and the electrostatic repulsive force acting horizontally between the two charged spheres. The system reaches equilibrium when the vector sum of these forces equals zero.

How can we calculate the angle at which the strings are inclined?

The angle of inclination of the strings can be calculated using trigonometric relationships. By resolving the forces into vertical and horizontal components, we can use the equilibrium conditions. The vertical component of the tension balances the weight of the sphere, and the horizontal component balances the electrostatic repulsive force. Using the tangent function, tan(θ) = (electrostatic force) / (gravitational force), we can find the angle θ.

What is the role of Coulomb's Law in this scenario?

Coulomb's Law is crucial in determining the magnitude of the electrostatic repulsive force between the two charged spheres. According to Coulomb's Law, the force (F) between two point charges is given by F = k * |q1 * q2| / r^2, where k is Coulomb's constant, q1 and q2 are the charges on the spheres, and r is the distance between the centers of the two spheres. This force acts horizontally and is a key component in the equilibrium analysis.

How does the mass of the spheres affect the equilibrium position?

The mass of the spheres affects the gravitational force acting on each sphere. A heavier sphere will have a greater gravitational force, which in turn affects the tension in the strings and the angle of inclination. Specifically, a larger mass will result in a smaller angle of inclination, given the same charge and distance between the spheres, because the vertical component of the tension must balance a greater weight.

What assumptions are typically made in analyzing this system?

Several assumptions are typically made to simplify the analysis of this system: (1) The spheres are treated as point charges. (2) The strings are massless and inextensible. (3) The system is in a vacuum, so air resistance and other forces are negligible. (4) The charges are static and do not change over time. (5) The distance between the spheres is much greater than the radius of the spheres, so edge effects are ignored.

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