- #1
RaamGeneral
- 50
- 1
It's not clear to me how I can balance the following equation, most of all because of K which I don't know how to deal with:
[tex]\mathrm{SO_2 + K_2Cr_2O_7 \to Cr_2(SO_4)_3 + SO_3}[/tex] [this is the text of the exercise]
It's acidic solution for sulfuric acid, so the equation can be better written so:
[tex]\mathrm{SO_2 + K_2Cr_2O_7 + H_2SO_4 \to Cr_2(SO_4)_3 + SO_3 + H_2O + K}[/tex] (I assume K has to be added, preserving the charge in both members)
To use the half-reaction method I write the ionic form:
[tex]\mathrm{SO_2+K^+ + Cr_2O_7^{2-}+H^+ \to Cr^{3+}+SO_3+H_2O + K}[/tex]
Writing and balancing three half-reactions (can it be?) I get:
[tex]\mathrm{4SO_2 + K_2Cr_2O_7+3H_2SO_4 \to 4SO_3 + Cr_2(SO_4)_3+2K+3H_2O}[/tex]Is it correct?
Thank you.
[tex]\mathrm{SO_2 + K_2Cr_2O_7 \to Cr_2(SO_4)_3 + SO_3}[/tex] [this is the text of the exercise]
It's acidic solution for sulfuric acid, so the equation can be better written so:
[tex]\mathrm{SO_2 + K_2Cr_2O_7 + H_2SO_4 \to Cr_2(SO_4)_3 + SO_3 + H_2O + K}[/tex] (I assume K has to be added, preserving the charge in both members)
To use the half-reaction method I write the ionic form:
[tex]\mathrm{SO_2+K^+ + Cr_2O_7^{2-}+H^+ \to Cr^{3+}+SO_3+H_2O + K}[/tex]
Writing and balancing three half-reactions (can it be?) I get:
[tex]\mathrm{4SO_2 + K_2Cr_2O_7+3H_2SO_4 \to 4SO_3 + Cr_2(SO_4)_3+2K+3H_2O}[/tex]Is it correct?
Thank you.