Balancing Charges on Identical Spheres

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In summary: So when they come together, they will neutralize each other and become (q1-q2)/2, creating a force of k(q1-q2)^2/4*d^2. Does that make sense? In summary, the conversation discusses two identical small metal spheres with initial charges q1 and q2 experiencing an attractive force when placed 1.0m apart. After being brought together and balancing their charges, they experience a repulsive force of the same magnitude. The solution involves using Coulomb's Law to calculate the net charge on the spheres and understanding that the charge on each sphere must be (q1 + q2)/2 in order for the forces to balance.
  • #1
Tridius
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Homework Statement




Two identical small metal spheres initially carry charges q_1 and q_2. When they're x=1.0m apart, they experience a 2.5N attractive force. Then they're brought together so charge moves from one to the other until they have the same net charge. They're again placed x=1.0m apart, and now they repel with a 2.5N force.

Homework Equations



F=kq1q2/r^2

The Attempt at a Solution



Alright, so this question seemed pretty easy but my answer isn't making any sense. First I solved for the net charge on the spheres after they had discharged,

F=kq3^2/r^2 ... q3=sqrt(Fr^2/k) = 1.667*10^-5C

Next I assumed that since the two spheres had balanced their charges, the original charges were 1.667*10^-5 +/- x.

Putting this back into the Coulomb's Law equation I got

F=k(1.667*10^-5 - x)(1.667*10^-5 + x)/r^2

But when I solved for x and then tried to sub it back into q1=(1.667*10^-5 - x) and q2=(1.667*10^-5 + x), both q1 and q2 were positive, which would not result in an attractive force.

Help please. =)
 
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  • #2
Hi Tridius. welcome to PF.
In the first case, F = k*q1*q2/d^2.
In the second case, charge on each sphere is (q1 - q2)/2
So F= k*(q1 - q2)^2/d^2
Can you proceed now?
 
  • #3
Thanks a lot, this should really help. What I don't understand though is that if the charges are now (q1-q2)/2, then why is the force k(q1-q2)^2/d^2? Where did the 2 in the denominator go?
 
  • #4
Tridius said:
Thanks a lot, this should really help. What I don't understand though is that if the charges are now (q1-q2)/2, then why is the force k(q1-q2)^2/d^2? Where did the 2 in the denominator go?
The force should be
F = k(q1-q2)^2/4*d^2
 
  • #5
I don't understand why each charge is (q1-q2)/2.
If it was, then the total charge would be 2*(q1-q2)/2 = q1-q2.
But we know the total charge is q1 + q2.
Looks like the charge on each must be (q1 + q2)/2.
 
  • #6
Delphi51 said:
I don't understand why each charge is (q1-q2)/2.
If it was, then the total charge would be 2*(q1-q2)/2 = q1-q2.
But we know the total charge is q1 + q2.
Looks like the charge on each must be (q1 + q2)/2.
Since the force is attractive, the charges must be of opposite nature.
 

FAQ: Balancing Charges on Identical Spheres

What are identical discharging spheres?

Identical discharging spheres refer to a set of spheres with the same size, shape, and material composition, which are connected to a power source and allowed to discharge their electrical charge.

How do identical discharging spheres work?

Identical discharging spheres work by transferring electrical charge from one sphere to another, creating a flow of electricity. This process continues until the spheres reach the same potential, resulting in a balanced discharge.

What is the significance of identical discharging spheres in science?

Identical discharging spheres are used in scientific experiments to study the principles of electricity and electrical charge transfer. They can also be used to demonstrate concepts such as electric potential, capacitance, and resistance.

Can identical discharging spheres have different charges?

Technically, identical discharging spheres should have the same amount of charge. However, in real-world scenarios, there may be slight variations due to factors such as imperfect connections or external influences.

How are identical discharging spheres different from non-identical ones?

The main difference between identical and non-identical discharging spheres is that the former have the same properties, while the latter may have varying sizes, shapes, or material compositions. This can affect the rate of discharge and the overall behavior of the spheres.

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