- #1
yoshi6
- 63
- 0
Hello, I am new at this, I am not exactly sure how this works. I have a question where I have to balance two equations using either the half-reaction or the oxidation number method... they are as follows.:
1. Co + MnO4- + H+ = Co+2 + Mn+2 + H2O
2. Cu + HNO3 = Cu(NO3)2 + NO + H2O
I am having trouble with the first one. I think I get the second one okay; I am not sure how to type the whole process so here is my final answer for 2;
3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O
Thankyou
1. Co + MnO4- + H+ = Co+2 + Mn+2 + H2O
2. Cu + HNO3 = Cu(NO3)2 + NO + H2O
I am having trouble with the first one. I think I get the second one okay; I am not sure how to type the whole process so here is my final answer for 2;
3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O
Thankyou