Balancing Mass: Solving for Bar Length

In summary, the bar has a mass of 3 grams/cm. When a mass of 15 grams is hung on the left side, the system is balanced. The length of the bar is 15 + x cm.
  • #1
IhasSwag
15
0
Moments.png

Homework Statement


The bar has a mass of 3 grams/cm. When a mass of 15 grams is hung on the left side, the system is balanced. Calculate the length of the bar.

Homework Equations


F1*r1 = F2*r2

The Attempt at a Solution


I thought that the moment on the left should be equal to the moment at the right, so it should be
mleft * g * rleft = mright* g *rright

But apparently it should be that the moment of the mass on the left side is equal to the moment of the whole bar.
Can someone explain why this is?
 
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  • #2
what is the mass of the right side
 
  • #3
the bar is 15cm on the right side. The mass is 3 grams / cm. So 45 grams.
 
  • #4
the center of mass on bar where is it ?
 
  • #5
IhasSwag said:
the bar is 15cm on the right side. The mass is 3 grams / cm. So 45 grams.
and length is not 15
it is 15 + x
 
  • #6
isn't the center of mass exactly in the middle?
 
  • #7
IhasSwag said:
isn't the center of mass exactly in the middle?
yes an it is in 15 + x /2
 
  • #8
so what is distance from center of mass to the thing that balances the bar
 
  • #9
I really don't know
 
  • #10
look on the picture the center of mass is exactly in the middle and i am asking you to tell what is distance between the center and the big black thing that is holing the bar
 
  • #11
is it: 15 - (15+x)/2 ?
 
  • #12
no but you were close (15 + x ) / 2 - x
edit : x doesn't belong to 2
 
  • #13
I see now that it is (15 + x ) / 2 - x
 
  • #14
if you got it than what can you say about forces
 
  • #15
They cancel out at the center of mass?
 
  • #16
nope what do you think is holding 15 grams from not falling
 
  • #17
The mass of the bar on the right side?
 
  • #18
what do you mean under mass on the right side do you say that it is smaller that hole mass of bar
 
  • #19
I meant the mass of the bar on the right side of the center of mass
 
  • #20
that is not correct in center of mall is localized hole mass so it fully acts on the "holder"
 
  • #21
mass of bar times distance from center of mass to "holder" equals to hung mass times distance from that mass to "holder" that is your equation
 

FAQ: Balancing Mass: Solving for Bar Length

How do I determine the mass of each side of the bar?

To determine the mass of each side of the bar, you will need to know the total mass of the bar, as well as the distance of each mass from the fulcrum. This can be calculated using the formula: Mass of one side = (Total mass * Distance of the other side from the fulcrum) / Distance of the side you are solving for.

What is the equation for balancing mass on a bar?

The equation for balancing mass on a bar is: Mass of one side * Distance of one side = Mass of the other side * Distance of the other side. This equation is based on the principle of lever arm equilibrium, where the forces on either side of the fulcrum must be equal to maintain balance.

How does the length of the bar affect the balancing of mass?

The length of the bar affects the balancing of mass by changing the distance from the fulcrum to each mass. The longer the bar, the greater the distance from the fulcrum to each mass, resulting in a larger lever arm and a smaller force needed to balance the masses. Conversely, a shorter bar will require a larger force to maintain balance.

Can the bar be balanced with different masses on each side?

Yes, the bar can be balanced with different masses on each side as long as the mass and distance values on either side of the fulcrum are proportional. For example, if one side has a mass of 2kg at a distance of 5m from the fulcrum, the other side must have a mass of 4kg at a distance of 2.5m to maintain balance.

What are some real-life applications of balancing mass on a bar?

Balancing mass on a bar is a fundamental concept in physics and has many real-life applications. Some examples include see-saws, balance scales, and weight distribution in construction and engineering. It is also used in chemistry experiments to measure and balance chemical reactions.

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