Nusc said:Can someone explain to me why E = .5(k/a)(e^2 - 1)/(1 - e^2) = .5(k/a)
The conjugate won't work, how do I show this?
Basic Algebra is the branch of mathematics that deals with operations and relationships involving variables, constants, and equations.
E = .5(k/a) is a mathematical expression that represents the relationship between three variables: E, k, and a. It indicates that E is equal to half of k divided by a.
The conjugate refers to the operation of multiplying the numerator and denominator of a fraction by the same expression, but with opposite signs. In this case, it is used to simplify the expression E = .5(k/a) to make it easier to solve.
To show E = .5(k/a) without using the conjugate, you can use the properties of fractions to simplify the expression. For example, you can multiply both sides by 2 to get rid of the decimal and then divide both sides by k to isolate E.
Understanding how to show E = .5(k/a) without using the conjugate is important because it demonstrates a deeper understanding of algebraic concepts and allows for more flexibility in solving equations. It also lays a strong foundation for more complex algebraic operations and problem-solving in the future.