Basic Derivative: ln[(sin(x)^3)^3] - Is it Correct?

  • Thread starter RJC
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In summary, the equation ln [(sin(x)^3)^3] can be simplified to 9 cot(x). The correct derivative is 9*x^2*cot(x^3), but a better notation is 9 cot(x).
  • #1
RJC
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Alright, here is the equation:

ln [(sin(x)^3)^3]

And here is my answer with some steps, please tell me if I'm wrong..

9 ln(sin'x)

9 (cos'x)/(sin'x)

Derivative= 9tan(x)^-1

is that correct?
 
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  • #2
I Get 9*x^2*cot(x^3)
It Looks Like U Forgot The X^2 Term When You Got The Der Of X^3
 
  • #3
Usually we say that [tex]\frac{1}{\tan(x)}=\cot(x)[/tex]. Looks good to me.
 
  • #4
soo.. which answer is correct? the whole sin'x is cubed, not just the x value within the sine..
 
  • #5
I see nothing wrong with your original answer, except for a better notation.
 
  • #6
so 9cot(x) would be a better answer?
 
  • #7
Yes, it's more concise and very standard.
 

FAQ: Basic Derivative: ln[(sin(x)^3)^3] - Is it Correct?

What is the basic derivative of ln[(sin(x)^3)^3]?

The basic derivative of ln[(sin(x)^3)^3] is 3(sin(x))^2cos(x).

How do you solve for the derivative of ln[(sin(x)^3)^3]?

To solve for the derivative of ln[(sin(x)^3)^3], you can use the chain rule and the derivative of ln(u) = (1/u)(du/dx). In this case, u = (sin(x)^3)^3. The derivative of u is 3(sin(x))^2cos(x), so the final answer is (1/u)(du/dx) = (1/(sin(x)^3)^3)(3(sin(x))^2cos(x)).

Can you simplify the derivative of ln[(sin(x)^3)^3]?

The derivative can be simplified to 3(sin(x))^2cos(x)/sin(x)^6.

Is the given derivative ln[(sin(x)^3)^3] correct?

Yes, the given derivative is correct. It follows the rules of logarithmic differentiation and the chain rule.

Are there any alternative ways to write the derivative of ln[(sin(x)^3)^3]?

Yes, you can also write the derivative as 3sin(x)cos(x). Additionally, you can expand the expression and write it as 3sin(x)^2cos(x)/sin(x)^3.

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