Basic high school algebra, with physics

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The discussion focuses on solving a problem involving an elastic collision between a photon and a stationary electron using conservation of energy and momentum. The participant acknowledges the relativity aspect but emphasizes that it ultimately requires basic algebra skills. They attempt to set up equations for energy and momentum conservation but struggle with the complexity introduced by the relativistic factor gamma. The solution involves expressing the energy conservation equation in terms of the electron's final momentum and substituting it into the momentum conservation equation to solve for the photon's momentum. The conversation highlights the challenge of integrating relativity into basic algebraic frameworks.
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"basic high school" algebra, with physics

Homework Statement


Consider a head-on, elastic collision between a massless photon (momentum po and energy Eo) and a stationary free electron. (a) Assuming that the photon bounces directly back with momentum p (in the direction of -po) and energy E, use conservation of energy and momentum to find p.


Homework Equations


E=\gammamc2
p=\gammamu
massless: E=pc
rest mass: E=mc2
E2=(pc)2+(mc2)2
v/c=pc/E
\gamma=1/\sqrt{1+(v/c)^2}

The Attempt at a Solution


Note:First of all I know that this is relativity, but it boils down to just plain algebra. I can't figure it out and help is hard to find, so if you can help I would really appreciate it.

I assume that p is the momentum of the electron. m=mass of the electron u=velocity of the electron c=speed of light

conserving energy: poc+mc2=pc+\gammamc2
po+mc=p+\gammamc
po=p+\gammamc-mc

conserving momentum: po=p-p=\gammamu-p

Plugging the result I got in conserving energy into the momentum equation:
p-p=p+\gammamc-mc
p=2p+mc(\gamma-1)
 
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The problem with the last line is that gamma has the speed of the electron (an unknown quantity) buried in it. Forget gamma. Write the energy conservation equation as

p_{0}c+mc^2=pc+\sqrt{(p_ec)^2+m^2c^4}

where pe is the final momentum of the electron.

Use the momentum conservation equation to replace pe with what it is equal to, then solve for p.
 
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