Basic QM: Probability Density w/ 3 Slits Open

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In summary, the probability density function for detecting a particle at a position x on the screen when only one particular slit is open is given by: (ψ*slit 1ψslit 3) + (ψ*slit 2ψslit 1) + (ψ*slit 3ψslit 1).
  • #1
phosgene
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Homework Statement



Suppose that we have a source of particles (e.g. photons) S, then three slits labelled 1,2 and 3, followed by a screen. For a particle that has passed through slit i, where i=1,2,3, let ψi(x) be the amplitude for the particle arriving at a position x units along the screen.

(a) Write down the probability density function for detecting a particle at a position x on the screen when:

1. all three slits are open,
2. slits 1 and 3 are open,

[Note: you don't need to determine explicit expressions for the amplitudes ψi(x)]

(b) If we applied purely classical physics, how would your answers to the above differ?

(c) Suppose we know the probability density functions for detecting the particle at a position x when only one particular slit is open. That is, we know P1(x), P2(x) and P3(x). Are we able to express the probability density function for the case of all three slits open in terms of P1(x), P2(x) and P3(x)? Can we do this if we apply purely classical physics?

Homework Equations





The Attempt at a Solution



(a) |ψslits 1,2,3|2= (ψ*slit 1 + ψ*slit 2 + ψ*slit 3)(ψslit 1 + ψslit 2 + ψslit 3)

= |ψslit 1|2 + |ψslit 2|2 + |ψslit 3|2 + ψ*slit 1ψslit 2 + ψ*slit 1ψslit 3 + ψ*slit 2ψslit 1 + ψ*slit 2ψslit 3 + ψ*slit 3ψslit 1 + ψ*slit 3ψslit 2

(b) The probability density functions would add linearly in classical physics, giving:

slits 1,2,3|2= |ψslits 1|2 + |ψslits 2|2 + |ψslits 3|2

(c) Well I would just plug the values for P(x) into the above equations for QM and classical physics, respectively, right?
 
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  • #2
For part (c): Is it possible to express P(x) in terms of just P1(x), P2(x), and P3(x)?
 
  • #3
Maybe not, because those probabilities don't take into account that the electron could interfere with itself. But it is possible in classical physics because the electron is just a particle.
 
  • #4
phosgene said:
Maybe not, ...

You should be able to give a definite answer by looking at your mathematical expression for the answer to (a). How would you write P1(x) in terms of ψslit 1, etc.?
 
  • #5
P1(x) could be written as ψ*slit 1ψslit 1, but my expression of the probability in a) includes terms like ψ*slit 1ψslit 3 which cannot be expressed in terms of P1(x), P2(x) or P3(x). Therefore I cannot express the probability in terms of just P1(x), P2(x) and P3(x). But in classical physics, the probability density functions add linearly, so I could express the probability in terms of P1(x), P2(x) and P3(x).
 
  • #6
Yes, I think that's what the question wanted.
 
  • #7
Great, thanks! :)
 

FAQ: Basic QM: Probability Density w/ 3 Slits Open

What is the concept of probability density in basic quantum mechanics?

Probability density is a fundamental concept in quantum mechanics that describes the likelihood of finding a particle at a specific location within a given space. It is represented by a mathematical function called the wave function, which describes the amplitude of the particle's wave-like behavior.

How does the probability density change when three slits are opened in a quantum experiment?

When three slits are opened in a quantum experiment, the probability density changes from a simple pattern with two slits to a more complex interference pattern. This is because the wave functions from the three slits interfere with each other, creating regions of higher and lower probability density.

What is the role of the slit width in determining the probability density in a quantum experiment?

The slit width plays a crucial role in determining the probability density in a quantum experiment. A wider slit will result in a broader, less defined interference pattern, while a narrower slit will produce a sharper and more defined pattern. This is due to the diffraction of the particle's wave function as it passes through the slit.

How does the distance between the slits affect the probability density in a quantum experiment?

The distance between the slits also has a significant impact on the probability density in a quantum experiment. As the distance between the slits increases, the interference pattern becomes more spread out, resulting in a decrease in the overall probability density. This is because the distance affects the phase difference of the wave functions, leading to constructive or destructive interference.

Can the probability density be measured directly in a quantum experiment?

No, the probability density cannot be measured directly in a quantum experiment. In quantum mechanics, the wave function represents the probability amplitude, not the actual probability of finding a particle at a specific location. The probability is determined by taking the square of the wave function, and the result is a probability density that can be observed through repeated experiments.

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