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RJLiberator
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Determine the singular points of each function:
f(z) = (z^3+i)/(z^2-3z+2)
So it is my understanding that a singular point is one that makes the denominator 0 in this case.
We see that (z-2)(z-1) is the denominator and we thus conclude that z =2, z=1 are singular points.
f(z) = (2z+1)/(z(z^2+1))
So, z=0, +/- i are singular points.
Am I understanding this correctly?
f(z) = (z^3+i)/(z^2-3z+2)
So it is my understanding that a singular point is one that makes the denominator 0 in this case.
We see that (z-2)(z-1) is the denominator and we thus conclude that z =2, z=1 are singular points.
f(z) = (2z+1)/(z(z^2+1))
So, z=0, +/- i are singular points.
Am I understanding this correctly?