Basketball player shoots a ball, find angle, parametrics

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A basketball player needs to determine the angle to shoot a ball traveling at 25 ft/sec from a height of 8 ft to reach a basket 10 ft high and 15 ft away. The equations of motion are expressed parametrically, with x(t) and y(t) representing horizontal and vertical positions over time. The player initially struggles with incorporating both time and angle into the equations but realizes that substituting time in terms of angle can help solve for the unknowns. After confirming the initial velocity, the player is set to proceed with the calculations. The discussion highlights the importance of correctly applying parametric equations in projectile motion problems.
Pi Face
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Homework Statement



A basketball player shoots a ball with a speed off 25 ft/sec from a point 15 ft horizontally away from the center of the basket. The basket is 10ft away above the the floor and the player releases the ball from a height of 8ft. At what angle should the player shoot the ball?


Homework Equations


Actually, this is one of my calc problems, but it seems physics-y enough to be posted here. I'm supposed to use parametrics to solve it.

x(t)=x0+h0t
y(t)= -(1/2)gt2+v0t+y0
h0=s0cos\theta
v0=s0sin\theta


The Attempt at a Solution



I don't feel like typing all these sub/superscripts, but I worked with the y(t) function, set v0 to 25 and y0 to 8 and got 0.0846 and 1.478 for values of t. But then I realizes that v0 was supposed to be s0cos\theta, which means I have both t and theta in the equation. How would I solve for either variable? Thanks.
 
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x(t) = vo*coaθ*t, where vo is the velocity of projection.
Find t = ...(1)
y(t) = yo + vo*sinθ*t - 0.5*g*t^2.
Substitute the appropriate values and find vo.
 
Uh...
how do I solve for t in x(t) = vo*cosθ*t?
am I supposed to get a number? i get t= x/(vo*cosθ)
 
Pi Face said:
Uh...
how do I solve for t in x(t) = vo*cosθ*t?
am I supposed to get a number? i get t= x/(vo*cosθ)
Yes.
 
yes to a number or yes I solved it right?

anyways, so then I substitute x/(vo*cosθ) for t in the y(t) equation? fun >.>
 
Pi Face said:
yes to a number or yes I solved it right?

anyways, so then I substitute x/(vo*cosθ) for t in the y(t) equation? fun >.>
Expression for t is correct.
Substitute in y(t) and solve for vo.
 
but what's theta? I have two unknowns, vo and theta.
 
Pi Face said:
but what's theta? I have two unknowns, vo and theta.
Vo = 25 ft/s.
 
can't believe i missed that. I am all set now. thanks!
 

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