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tnhoots
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Homework Statement
A basketball player who is 2.00 m tall is standing on the floor L = 8.0 m from the basket, as in Figure P4.54. If he shoots the ball at a 30.0° angle with the horizontal, at what initial speed must he throw so that it goes through the hoop without striking the backboard? The basket height is 3.05 m.
Homework Equations
y=Yo+Voyt-(g/2)t squared
X=Xo+Voxt-(g/2)t squared
The Attempt at a Solution
Vxo=cos(30)
Vyo=sin(30)
Vo (cos 30)=8
3.05=2.00+Vo-4.9t squared
3.05=10-4.9t squared
t=square root (6.95/4.9)
=1.191
Vo=8/(.7071*1.191)
=9.499
However, this is wrong...any suggesions??