- #1
ben774
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Homework Statement
iv been given this problem having attmepted it I am stuck when it comes to calculating maximum torque and can't seem to find any equations to help me out.
in a belt drive system the speed of the belt over the pulleys is 170/min. The initial tension of the belt is 400N and the tension on the tight side is 700N. if the Driver pulley is 300mm diameter and the ddriven pulley is 180mm diameter. calculate:
a) The power tramsmitted by the belt drive
b) The maximum torque output
any help would be much appriciated!
Homework Equations
power transmitted P=(T2-T1)V
where T1 = tight side and T2 = slack side
v= wr rads/s
The Attempt at a Solution
iv attempted part a) which i got
(700-400)v
170/0.3 = 180.4
180 x 2[tex]\check{}\Pi[/tex]/60 = 18.89
v = 18.89 x 0.3 = 5.67
P= (700-400)5.67=1.7 kw