- #1
keng
- 10
- 0
hi all, I'm little confuse about the relation of these two equation.
is it right to say that Bernoulli's equation is just a case(incompressible,inviscid,steady) of navier stoke equation?
is it right to say that Bernoulli's equation is just a case(incompressible,inviscid,steady) of navier stoke equation?