- #1
Brian T
- 130
- 31
From my astrophysics class, we were given that the minimum altitude of a star relative to your latitude on Earth ([itex]\phi[/itex]) is given by:
$$h_{min} = \delta + \phi - 90°$$ (where [itex]\delta[/itex] is the declination angle of the star)
Supposing you were trying to view as many stars as possible in the night sky (assuming perfect weather conditions / no light pollution everywhere on the Earth), where would be the best place to go?
Using the formula, you want [itex]h_{min}[/itex] to be as positive as possible for any given star declination [itex]\delta[/itex]. This means you should make you [itex]\phi[/itex] as large as possible, which would be 90 degrees (i.e. North pole). Is my reasoning correct, from this formula, that the best place to view as many stars as possible (again assuming perfect weather) would be at the north pole?
$$h_{min} = \delta + \phi - 90°$$ (where [itex]\delta[/itex] is the declination angle of the star)
Supposing you were trying to view as many stars as possible in the night sky (assuming perfect weather conditions / no light pollution everywhere on the Earth), where would be the best place to go?
Using the formula, you want [itex]h_{min}[/itex] to be as positive as possible for any given star declination [itex]\delta[/itex]. This means you should make you [itex]\phi[/itex] as large as possible, which would be 90 degrees (i.e. North pole). Is my reasoning correct, from this formula, that the best place to view as many stars as possible (again assuming perfect weather) would be at the north pole?