- #1
Gloyn
- 41
- 0
Hi!
I've got a problem with question 5 on this paper:
http://www.freeexampapers.com/past_papers.php?l=Past_Papers%2FAEA%2FPhysics%2F2006/
Download AEA-PHYS-PP-MayJune-2006-AEA-Paper-1342.pdf.
Starting from b) i), we got that:
ε=Δ∅/Δt → W=εe
Where W is denotes work, ε is e.m.f
Also, for ii) work can be written as:
W=2∏rF
in iv) we use F=Δp/Δt=2erΔB/Δt
as during one cycle mementum changes its direction to the opposite twice. From all that we got:
Δ∅=4∏r^2ΔB
Where 4 comes from? It should be deltaB times area of loop. I tried to check it if 2s does not cancel each other but they don't, where's the mistake?
I've got a problem with question 5 on this paper:
http://www.freeexampapers.com/past_papers.php?l=Past_Papers%2FAEA%2FPhysics%2F2006/
Download AEA-PHYS-PP-MayJune-2006-AEA-Paper-1342.pdf.
Starting from b) i), we got that:
ε=Δ∅/Δt → W=εe
Where W is denotes work, ε is e.m.f
Also, for ii) work can be written as:
W=2∏rF
in iv) we use F=Δp/Δt=2erΔB/Δt
as during one cycle mementum changes its direction to the opposite twice. From all that we got:
Δ∅=4∏r^2ΔB
Where 4 comes from? It should be deltaB times area of loop. I tried to check it if 2s does not cancel each other but they don't, where's the mistake?