- #1
agnibho
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Homework Statement
Find an approximation of (0.99)5 using the first three terms of its expansion.
2. The attempt at a solution
To get to the binomial theorem I divided 0.99 into
(0.99)5 = (1-0.01)5 = {1+(-0.01)}5
Then,
T1 = 5C0(1)5 = 1 x 1=1
T2 = 5C1(1)5-1(-0.01)1 = 5x1x -0.01= (-0.05)
T3 = 5C2(1)5-2(-0.01)2 = 10 x 1x 0.0001 = (0.001)
Now do I add them?? But adding them doesn't get me to the answer. Please help. Thanks in advance.