Binomial Theorem Proof: (nC0)(mC0) + (nC1)(mC1) + ... + (nCm)(mCm) = (n+m C m)

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The discussion focuses on proving the binomial theorem identity (nC0)(mC0) + (nC1)(mC1) + ... + (nCm)(mCm) = (n+m C m). Participants suggest using proof by induction, specifically on the variable m, to establish the identity. The initial assumption involves proving that the sum holds for m and then demonstrating it for m+1. There is a consensus that this method is a valid approach to tackle the proof. The conversation emphasizes the importance of understanding the principles of combinatorial identities in the context of the binomial theorem.
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Homework Statement



To Prove:
(nC0)(mC0) + (nC1)(mC1) + ... + (nCm)(mCm) = (n+m C m)

where nC0 = n choose 0 and so on.

Homework Equations





The Attempt at a Solution


Tried expanding the whole thing using factorials - but didn't work. Any hints would be really welcome!
 
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You should review proof by induction and then try to apply it here.
 
Do I do induction on m?? So that would mean , that by assumption ...+(nCm)(mCm) = (n+m C m)...then to prove ...+(nCm+1)(m+1Cm+1) = (n+m+1 C m+1) ...correct?
 
Yes, that should work.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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