- #1
arlesterc
- 43
- 3
A couple of points I need clarification on.
Objects outside of the event horizon feel the pull of the black hole - so the closer the object is to the event horizon but still outside of it the more pull the object feels to be sucked into the event horizon? Is that the correct view?
As far as virtual pair production that leads to Hawking radiation. Does it take place on the event horizon or just outside of it? In either case assuming one of the pair gets sucked into the black hole and the other doesn't, I am not following how energy is lost. So assuming we are talking about virtual photons - one virtual photon goes into the black hole /crosses the event horizon - maybe it was right on the horizon to start with - and the other dashes off. How does this cause the black hole to lose anything? It seems to me it gained a photon and the one that dashed away was never part of the black hole to begin with. So it seems it would look like the black hole has more energy/mass than it began with after such an event - one virtual photon to be exact. How does the black hole provide energy/mass to the photon that was never inside of it to the point the black hole loses energy/mass? I guess the deeper mystery to me is how energy is lost by gravity being just gravity? If you have a huge mass exerting gravity the concept of 'radiation' applied to it would seem to be equivalent to saying that if another much smaller object is brought close to it and starts feeling the force of gravity some of the mass/energy of the large object is lost because there is something close by to feel its gravity - if there was no such nearby object then 'gravity' would not 'lose energy'. Any assistance in clearing this up would be greatly appreciated.
Objects outside of the event horizon feel the pull of the black hole - so the closer the object is to the event horizon but still outside of it the more pull the object feels to be sucked into the event horizon? Is that the correct view?
As far as virtual pair production that leads to Hawking radiation. Does it take place on the event horizon or just outside of it? In either case assuming one of the pair gets sucked into the black hole and the other doesn't, I am not following how energy is lost. So assuming we are talking about virtual photons - one virtual photon goes into the black hole /crosses the event horizon - maybe it was right on the horizon to start with - and the other dashes off. How does this cause the black hole to lose anything? It seems to me it gained a photon and the one that dashed away was never part of the black hole to begin with. So it seems it would look like the black hole has more energy/mass than it began with after such an event - one virtual photon to be exact. How does the black hole provide energy/mass to the photon that was never inside of it to the point the black hole loses energy/mass? I guess the deeper mystery to me is how energy is lost by gravity being just gravity? If you have a huge mass exerting gravity the concept of 'radiation' applied to it would seem to be equivalent to saying that if another much smaller object is brought close to it and starts feeling the force of gravity some of the mass/energy of the large object is lost because there is something close by to feel its gravity - if there was no such nearby object then 'gravity' would not 'lose energy'. Any assistance in clearing this up would be greatly appreciated.