Block on top of an inclined plane, with a rough surface, that moves with constant acceleration

In summary, a block placed on an inclined plane with a rough surface moves with constant acceleration due to the interplay of gravitational force, friction, and the incline's angle. The gravitational force can be divided into components parallel and perpendicular to the incline, while friction opposes the motion. The net force acting on the block determines its constant acceleration, which can be calculated using Newton's second law, considering both the incline's angle and the coefficient of friction. This scenario illustrates the complexities of motion on inclined surfaces with friction.
  • #36
kuruman said:
Why can it not increase past that point?
Because friction can no longer hold the block still.
 
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  • #37
Thermofox said:
Because friction can no longer hold the block still.
Right. So friction has reached its upper limit. Remeber post #25
Thermofox said:
If I can say that then yes. I have 2 unknowns and 2 equations.
Can you say that ?
 
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  • #38
kuruman said:
Right. So friction has reached its upper limit. Remeber post #25

Can you say that ?
Yes, because
 
  • #39
So go ahead and solve the system. The algebra is much simpler if you replace the values
right from the start.
 
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  • #40
;

.

If I solve the system using the frame of reference where the x-axis is parallel to the slope I should obtain the same right?
 
  • #41
I agree with your solution. More presicely

Yes, the magnitude of the acceleration is a scalar and does not depend on how you choose your axes. Usually, the algebra is simpler if you choose them so that the acceleration is along one of the principal axes.
 
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  • #42
kuruman said:
I agree with your solution. More presicely

Yes, the magnitude of the acceleration is a scalar and does not depend on how you choose your axes. Usually, the algebra is simpler if you choose them so that the acceleration is along one of the principal axes.
That's great to hear. Thanks for your immense patience!!
 
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