- #1
axer
- 35
- 4
Moved from a technical forum, so homework template missing
Hello, this isn't a homework or anything, I am just trying to understand one thing :) (finals are tomorrow :-0 )
If a person is exposed to heat energy of the sun for 4 hours(5040000 J per hour) and the avg surface area of the person is 1.9 m^2. and specific heat capacity of the body is 3470 J kg-1 k-1. mass of the person is 70. Calculate the rise of Temp.
Q=mc(delta T)
So here's what I am not understanding.. Should I include the person's area? but I am not seeing why they included that since the formula doesn't state area.
Answer in which area is included: (5040000*4)(1.9)=(70)(3470)T ... 158 C.
removing area from the answer: ... 83 C.
If a person is exposed to heat energy of the sun for 4 hours(5040000 J per hour) and the avg surface area of the person is 1.9 m^2. and specific heat capacity of the body is 3470 J kg-1 k-1. mass of the person is 70. Calculate the rise of Temp.
Q=mc(delta T)
So here's what I am not understanding.. Should I include the person's area? but I am not seeing why they included that since the formula doesn't state area.
Answer in which area is included: (5040000*4)(1.9)=(70)(3470)T ... 158 C.
removing area from the answer: ... 83 C.