- #1
kavamo
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Homework Statement
A tungsten filament in a lamp is heated to a temperature of 2.30 x 10^3 K by an electric current. The tungsten has an emissivity of 0.31. What is the surface area of the filament if the lamp delivers 35.0 W of power?
Homework Equations
Stefan's Law(a greek letter that looks like P?) P(net)=ekAT^4
The Attempt at a Solution
35.0=0.31(5.670x10^-8 w/m^2*K^4)(2.30*10^3)^4A
35.0 = 491876.5257A
35.0/491876.5257=A
7.1156069x10^-5
is this correct?
Thanks in advance for your help.