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physicsquest
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Homework Statement
A golf ball released from a height of 1.5m above a concrete floor bounces back to a height of 1.1m. If the ball is in contact with the floor for 6.2 X 10^-4 s, what is the average acceleration of the ball while in contact with the floor?
g= 9.81 m/s^2
x-xo= -1.5
vo= 0
t= 6.2 X 10^-4
Are these variables all correct?
Homework Equations
t= ((-2(x-xo))/g)^(-1/2)
average acceleration= (v2-v1)/(t2-t1)
The Attempt at a Solution
t= ((-2(-1.5m)/(9.81m/s^2))^(1/2)= 0.55s
Do I take initial velocity divided by this time number?
And is final velocity just 1.1 divided by time?