- #1
ccastro306
- 2
- 0
Bowling physics... 10 pin bowling...
I'm an avid bowler... and trying to figure out the reduction in force into the pins when using a 14lb ball as opposed to a 15 lb ball as opposed to a 16 lb ball. I am reasoning that a lighter ball has less impact power (as in getting hit with a 3 lb brick as opposed to a 3 lb feather ball)
Obviously the hardness of the balls is the same, as is the ability to compress/absorb energy.
I know that I can throw the 15lb ball harder than the 16, and the 14 pounder harder still, but I'm wondering how MUCH harder I need to throw it to have the same force into the pins at impact (hand and wrist action, directional change and revolutions assumed to be equal)
I know that F=MA, but there really isn't any acceleration going on. The ball is a roughly constant speed into the pins (though it would slow down as it's going down the lane)
What is the formula for calculating the relative force into the pins of different weight balls?
Chris
I'm an avid bowler... and trying to figure out the reduction in force into the pins when using a 14lb ball as opposed to a 15 lb ball as opposed to a 16 lb ball. I am reasoning that a lighter ball has less impact power (as in getting hit with a 3 lb brick as opposed to a 3 lb feather ball)
Obviously the hardness of the balls is the same, as is the ability to compress/absorb energy.
I know that I can throw the 15lb ball harder than the 16, and the 14 pounder harder still, but I'm wondering how MUCH harder I need to throw it to have the same force into the pins at impact (hand and wrist action, directional change and revolutions assumed to be equal)
I know that F=MA, but there really isn't any acceleration going on. The ball is a roughly constant speed into the pins (though it would slow down as it's going down the lane)
What is the formula for calculating the relative force into the pins of different weight balls?
Chris