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dtseng96
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Homework Statement
A truck with a steel bed carries a wooden box, where μs = 2μk. The box of mass m is in the middle of the bed of length l. If the truck is moving forward with velocity vo but is slowing down, determine the maximum distance the truck can take to stop before the box hits the cabin of the truck in terms of the variables given.
Homework Equations
F = ma, Fk = μkmg
The Attempt at a Solution
So my teacher said that the acceleration of the box relative to the truck is aB = μkg, while the acceleration of the truck relative to the ground is aT = -μkg. I'm having trouble understanding how my teacher got this... I do know that the acceleration of the block relative to the ground is a = μg, but I don't know how my teacher got the acceleration of the block relative to the truck. Can anyone help clarify my teacher's reasoning?
Any help is appreciated. Thank you so much!
In case you guys want to look at my teacher's actual solution, here it is. My question is about part b): https://dl.dropbox.com/u/12682457/m%20%26%20f%20%232%20copy.jpg
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