- #36
Chris Hillman
Science Advisor
- 2,355
- 10
More on the alleged counterexample
Ben and all:
The confusions here have to do with elementary curve theory, nothing hard, but a bit frustrating so we all need to try to be patient.
George, what you did is correct, but I don't think it helps: we really need to use an affine parameter, and if we can find an affine parameter for a timelike curve, it's trivial to turn it into an arc length parameter, which is what we really want to use.
Ben, trying to define a congruence not as a family of parameterized curves but as a family of unparameterized curves is generally a bad idea:
Example: consider the euclidean plane curve
[tex]
y = \sqrt{1-x^2}
[/tex]
To parameterize it by some w (not neccessarily an affine parameter!) is easy:
[tex]
x = w, \; y = \sqrt{1-w^2}
[/tex]
Here, w is an unknown function of the arc length parameter s. By definition of arc length in E^2 (cartesian chart, obviously), we have
[tex]
1 = \left( \frac{dx}{ds} \right)^2 + \left( \frac{dy}{ds} \right)^2
= \dot{w}^2 + \frac{\dot{w}^2 \, w^2}{1-w^2}
= \frac{\dot{w}^2}{1-w^2}
[/tex]
which gives [itex]w = \sin(s)[/itex]. So our arc length parameterization is
[tex]
x = \sin(s), \; y = \cos(s)
[/tex]
Now try the same procedure in E^{1,1} (with appropriate signature change) with
[tex]
x = k \, \exp(t)
[/tex]
You can find the ODE for the naive parameter in terms of the arc length parameter, but it is not easy to find its solution in closed form, agreed?
Ben, can you try to come up with an example of whatever you are trying to illustrate which is given as an explicit congruence of proper time parameterized curves? Or if you can clearly restate what you were trying to show, maybe I can come up with an example myself.
Ben and all:
The confusions here have to do with elementary curve theory, nothing hard, but a bit frustrating so we all need to try to be patient.
George, what you did is correct, but I don't think it helps: we really need to use an affine parameter, and if we can find an affine parameter for a timelike curve, it's trivial to turn it into an arc length parameter, which is what we really want to use.
Ben, trying to define a congruence not as a family of parameterized curves but as a family of unparameterized curves is generally a bad idea:
- the theory requires us to work with the unit vector field underlying a congruence of proper time parameterized (or arc length parameterized) curves, so if the curves are not presented as parameterized curves, we will need to parameterize them and then convert that to an arc length parameterization,
- even in simple examples, it can be quite difficult to find explicitly an arc length parameterization or proper time parameterization
Example: consider the euclidean plane curve
[tex]
y = \sqrt{1-x^2}
[/tex]
To parameterize it by some w (not neccessarily an affine parameter!) is easy:
[tex]
x = w, \; y = \sqrt{1-w^2}
[/tex]
Here, w is an unknown function of the arc length parameter s. By definition of arc length in E^2 (cartesian chart, obviously), we have
[tex]
1 = \left( \frac{dx}{ds} \right)^2 + \left( \frac{dy}{ds} \right)^2
= \dot{w}^2 + \frac{\dot{w}^2 \, w^2}{1-w^2}
= \frac{\dot{w}^2}{1-w^2}
[/tex]
which gives [itex]w = \sin(s)[/itex]. So our arc length parameterization is
[tex]
x = \sin(s), \; y = \cos(s)
[/tex]
Now try the same procedure in E^{1,1} (with appropriate signature change) with
[tex]
x = k \, \exp(t)
[/tex]
You can find the ODE for the naive parameter in terms of the arc length parameter, but it is not easy to find its solution in closed form, agreed?
Ben, can you try to come up with an example of whatever you are trying to illustrate which is given as an explicit congruence of proper time parameterized curves? Or if you can clearly restate what you were trying to show, maybe I can come up with an example myself.
Last edited: