- #1
lornstone
- 6
- 0
Hi,
I am reading the BRST Symmetry section of Peskin and Schroeder but I can't find anywhere
why the BRST transformation for the gauge vector,
[tex] \delta A_\mu^a = \varepsilon \partial_\mu c^a [/tex]
implies that only forward polarized states can create ghosts by applying Q, Q being define by
[tex] \delta \phi = \varepsilon Q \phi [/tex]
I saw in a paper that it's obvious when we go to momentum space, but unfortunately it's not for me...
Thank you!
I am reading the BRST Symmetry section of Peskin and Schroeder but I can't find anywhere
why the BRST transformation for the gauge vector,
[tex] \delta A_\mu^a = \varepsilon \partial_\mu c^a [/tex]
implies that only forward polarized states can create ghosts by applying Q, Q being define by
[tex] \delta \phi = \varepsilon Q \phi [/tex]
I saw in a paper that it's obvious when we go to momentum space, but unfortunately it's not for me...
Thank you!