- #1
ardentmed
- 158
- 0
Hey guys, I'm having trouble with this problem set I'm working on at the moment. I'd appreciate some help with this question:
(I'm only asking about number two. Ignore number one please.)
So if the length for the hypotenuse of the leftmost triangle is represented by:
c^2 = x^2 + y^2
Then,
c= √(2500 + x^2)
Therefore, the total cost comes to:
C(x) = 400,000-20,000x + 50,000√(2500 + x^2)
Am I on the right track?
Moreover, we need to optimize and deduce the minimum cost, x's smallest possible value:
c'(x) = dy/dx (400,000-20,000x + 50,000√(2500 + x^2))
Then isolate and solve for "x."
x=21.821789 km
x ~ 21.km.
Thanks in advance.
(I'm only asking about number two. Ignore number one please.)
So if the length for the hypotenuse of the leftmost triangle is represented by:
c^2 = x^2 + y^2
Then,
c= √(2500 + x^2)
Therefore, the total cost comes to:
C(x) = 400,000-20,000x + 50,000√(2500 + x^2)
Am I on the right track?
Moreover, we need to optimize and deduce the minimum cost, x's smallest possible value:
c'(x) = dy/dx (400,000-20,000x + 50,000√(2500 + x^2))
Then isolate and solve for "x."
x=21.821789 km
x ~ 21.km.
Thanks in advance.