- #1
j88k
- 27
- 0
Homework Statement
A 75 g bungee cord has an equilibrium length of 1.20 m. The cord is stretched to a length of 1.80 m, then vibrated at 20 Hz. This produces a standing wave with two antinodes.
What is the spring constant of the bungee cord?
Homework Equations
f=nv/2L
The Attempt at a Solution
Two anti-nodes mean 3 harmonics
f = 20Hz
n = number of harmonics
L = length
v = velocity
20 = nv/(2L)=3v/(2L)
v = 20/3*2*1.8 =24m/s
F = tension
v^2 = F/(linear mass density)
F = 24^2 * 0.075/1.8
F = 24N
F = kx
k =F/x
k = 24/(1.8-1.2) = 40N/m
i
It doesn't seem to be right though!