- #1
swell9
- 10
- 0
Hello,
This is bugging me so I'd appreciate any help.
I have two objects made from the same material with the same mass.
The base of Object 2 is 3 times that of Object 1. If I place the objects base first in a liquid, why is the buoyant force on them equal?
What here is what I'm thinking:
V[itex]_{ submerged}[/itex]= (Density[itex]_{ object}[/itex] X Volume[itex]_{ object}[/itex]) / (Density[itex]_{ liquid}[/itex])
Since the volume of the two objects has to be different if they are of the same material and of the same mass, the volume submerged of each will also be different.
Doesn't this give that the Buoyant force will also be different?
Thanks for your time.
This is bugging me so I'd appreciate any help.
I have two objects made from the same material with the same mass.
The base of Object 2 is 3 times that of Object 1. If I place the objects base first in a liquid, why is the buoyant force on them equal?
What here is what I'm thinking:
V[itex]_{ submerged}[/itex]= (Density[itex]_{ object}[/itex] X Volume[itex]_{ object}[/itex]) / (Density[itex]_{ liquid}[/itex])
Since the volume of the two objects has to be different if they are of the same material and of the same mass, the volume submerged of each will also be different.
Doesn't this give that the Buoyant force will also be different?
Thanks for your time.