C.O.P/Refrigerator (Finding Temp)

  • Thread starter HugoPang1
  • Start date
In summary, the question is asking for the temperature of the surrounding room in Celsius, given that a refrigerator is operating at a C.O.P of 0.98 and the temperature of the freezer compartment is -12 Celsius. The most efficient thermodynamic cycle would be the Carnot process, with an ideal C.O.P of 0.98/0.13. In order to find the temperature of the surrounding room, we can use the relationship between Qo and Q1 in the Carnot process, and the known temperature of the hot reservoir (261 K) to calculate the temperature of the cold reservoir (295 K).
  • #1
HugoPang1
3
0

Homework Statement



A refrigerator is operating at a C.O.P of 0.98, which is 13% of the max C.O.P theoretically possible. The temperature of the freezer compartment of the refrigerator is -12 Celsius. What is the temperature of the surrounding room (in Celsius)?

Homework Equations



C.O.P = Qo/W

The Attempt at a Solution



Cannot interpret the question correctly
 
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  • #2
HugoPang1 said:

Homework Statement



A refrigerator is operating at a C.O.P of 0.98, which is 13% of the max C.O.P theoretically possible. The temperature of the freezer compartment of the refrigerator is -12 Celsius. What is the temperature of the surrounding room (in Celsius)?

Homework Equations



C.O.P = Qo/W

The Attempt at a Solution



Cannot interpret the question correctly
What kind of thermodynamic cycle would be the most efficient (highest COP)? What is the expression for that highest COP in terms of temperature of the hot and cold reservoirs? What is Qo?

AM
 
  • #3
Assume Qo is energy taken from freezer and Q1 is energy released after each cycle. For Carnot process

T1/To equals Q1/Qo

Also W equals Q1 - Qo

In ideal case cop equals 0.98/.13, because we know in non ideal case cop is .98

But cop equals Qo/(Q1-Qo) take reciprocal hence get Q1/Qo, from which use relationship with T1 and To to get T1. Remember that To is 261. My answer is around 295K

Hope I haven't given too much away
 

FAQ: C.O.P/Refrigerator (Finding Temp)

What is the purpose of finding the temperature in a C.O.P/refrigerator?

The purpose of finding the temperature in a C.O.P/refrigerator is to ensure that the system is operating efficiently and maintaining the desired temperature for storing or cooling items. This helps to prevent spoilage of food or other items and can also save energy and money.

How do you find the temperature in a C.O.P/refrigerator?

The temperature in a C.O.P/refrigerator can be found by using a thermometer or temperature probe. This device is placed inside the refrigerator or in the area being cooled and displays the current temperature.

What is the ideal temperature range for a C.O.P/refrigerator?

The ideal temperature range for a C.O.P/refrigerator is between 35-38 degrees Fahrenheit (2-3 degrees Celsius). This range is considered safe for storing most perishable items and also helps to maintain the efficiency of the system.

Why is it important to regularly check the temperature in a C.O.P/refrigerator?

Regularly checking the temperature in a C.O.P/refrigerator is important because it can help detect any potential issues with the system, such as a malfunctioning thermostat or a leak. It also ensures that the system is maintaining the desired temperature and preventing food spoilage.

Are there any other factors that can affect the temperature in a C.O.P/refrigerator?

Yes, there are other factors that can affect the temperature in a C.O.P/refrigerator, such as the amount of items being stored, the frequency of door openings, and the location of the refrigerator (e.g. near a heat source). It is important to consider these factors when monitoring the temperature and adjusting the settings if necessary.

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