- #1
sonofjohn
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The function f is continuous on the closed interval [2,8] and has va;ues that are given in the table below. Using sub intervals [2,5]. [5,7], and [7,8], what is the trapezoidal approximation of the anti derivative from 2 to 8 of f(x)dx?
|x| |2|5|7|8|
f(x)| |10|30|40|20|
(a) 110 (b) 130 (c) 160 (d) 190 (e) 210
trapezoid rule= anti derivative from a to b is f(x)dx=Tn= change of x/2*[f(x1) + 2f(x2) + ... + 2f(xn-1) + f(xn)]
I tried using the formula and plugging the information in exluding the point at [7,40] because it doesn't have the same change in x as the other numbers. Although the equation doesn't specify what the interval count is but rather that I have to use all the intervals. Therefore I don't really know how to use the 3rd interval [7,40] in the problem.
|x| |2|5|7|8|
f(x)| |10|30|40|20|
(a) 110 (b) 130 (c) 160 (d) 190 (e) 210
trapezoid rule= anti derivative from a to b is f(x)dx=Tn= change of x/2*[f(x1) + 2f(x2) + ... + 2f(xn-1) + f(xn)]
I tried using the formula and plugging the information in exluding the point at [7,40] because it doesn't have the same change in x as the other numbers. Although the equation doesn't specify what the interval count is but rather that I have to use all the intervals. Therefore I don't really know how to use the 3rd interval [7,40] in the problem.