- #1
mikky05v
- 53
- 0
I'm trying to do this homework problem but I keep getting an answer that is not given. Can someone tell me what I am doing wrong please. This is for University level calc 3.
A vector U=<x,y>
||U|| means the length of U = √(x^2 +y^2). vectors can also be written as U = ||U||(cosθi, sinθj)
so I start by naming the vectors.V is the direction the plane is now heading. V1 is the original direction of the plane. V2 is the direction of the wind.
V = V1 + V2
V1 = 600(cos148i+sin148j)
V2 = 80(cos45i+sin45j)
next I distributed, combined like terms and factored out i and j
V = (600cos148+80cos45)i + (600sin148+80cos45)j
I plugged that into my calculator and got
V = <-452.7i + 374.5j>
To find the speed I found the length of vector V
||V|| = sqrt[ (-452.7)2+374.52] = 587.5 km/hr
That isn't one of the options.. am i wrong?
Homework Statement
Homework Equations
A vector U=<x,y>
||U|| means the length of U = √(x^2 +y^2). vectors can also be written as U = ||U||(cosθi, sinθj)
The Attempt at a Solution
so I start by naming the vectors.V is the direction the plane is now heading. V1 is the original direction of the plane. V2 is the direction of the wind.
V = V1 + V2
V1 = 600(cos148i+sin148j)
V2 = 80(cos45i+sin45j)
next I distributed, combined like terms and factored out i and j
V = (600cos148+80cos45)i + (600sin148+80cos45)j
I plugged that into my calculator and got
V = <-452.7i + 374.5j>
To find the speed I found the length of vector V
||V|| = sqrt[ (-452.7)2+374.52] = 587.5 km/hr
That isn't one of the options.. am i wrong?