- #1
Allenman
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I mostly just want to know if I did this correctly... And if not, where I went wrong.
Of [itex]\overline{U}[/itex]=(-2, 6) is the vector [itex]\overline{AB}[/itex] and the midpoint of the line segment from A to B has the coordinates (2,1). Find A and B.
Let
[itex]\overline{A}[/itex]=(a1, a2)
[itex]\overline{B}[/itex]=(b1, b2)
[itex]\overline{AB}[/itex]=(a1, b1) + t(b1-a1, b2-a2)
rearranging I got:
[itex]\overline{AB}[/itex]=(1-t)(a1, b1) + t(a2, b2)
So when t=0 I have the coordinates (a1 and b1)
and when t=1 I have the coordinates (a2 and b2)
So plugging the numbers:
[itex]\overline{AB}[/itex]=(-2,6) + t(-2 - 2, 6 - 1)
=(1-t)(-2, 6) + t(2, 1)
[itex]\overline{A}[/itex]=(-2, 2)
[itex]\overline{B}[/itex]=(6, 1)
Did I do it right? or am I way off?... lol
Homework Statement
Of [itex]\overline{U}[/itex]=(-2, 6) is the vector [itex]\overline{AB}[/itex] and the midpoint of the line segment from A to B has the coordinates (2,1). Find A and B.
Let
[itex]\overline{A}[/itex]=(a1, a2)
[itex]\overline{B}[/itex]=(b1, b2)
Homework Equations
The Attempt at a Solution
[itex]\overline{AB}[/itex]=(a1, b1) + t(b1-a1, b2-a2)
rearranging I got:
[itex]\overline{AB}[/itex]=(1-t)(a1, b1) + t(a2, b2)
So when t=0 I have the coordinates (a1 and b1)
and when t=1 I have the coordinates (a2 and b2)
So plugging the numbers:
[itex]\overline{AB}[/itex]=(-2,6) + t(-2 - 2, 6 - 1)
=(1-t)(-2, 6) + t(2, 1)
[itex]\overline{A}[/itex]=(-2, 2)
[itex]\overline{B}[/itex]=(6, 1)
Did I do it right? or am I way off?... lol