Calc 4 Student, Please help me understand Existance and Uniqueness

In summary, Dane is thinking about the theorem in terms of 3 dimensions, and imagines f and its partial to be continuous "ON" the rectangle, not "IN" the rectangle. He is unsure if this is the correct way to think about it, and would welcome critique of his draft paper.
  • #1
danerape
32
0
Ok, after going thru the proof, the only think that still eludes me is the region of definition given in the theorem itself. The rectangle where f and the partial of f with respect to y are known to be continuous.

I am thinking of this three dimensionally, and I do not know if this is the correct way to think about it? In other words, I am imagining that f and its partial are continuous "ON" the rectangle, not "IN" the rectangle. I have seen the theorem written with both words.

My 3-d take on this is that f and its partial are known continuous at every point, (x,y), within the confines of the rectangle. I am imagining f and its partial to be graphed in the z direction in other words.

I think I am confused about this because of the nature of picard iteration, where y is a function of x. I am considering y to be independent of x in my thinking, this is why I am not sure it is right.

So, is it true that continuity of f and its partial exist at every interior point in the rectangle?

Is it correct to think of this three dimensionally, as if f and the partial are being graphed ON the rectangle in the z direction.

ALSO, I HAVE A ROUGH DRAFT OF A PAPER I AM WRITING FOR STUDENTS WORKING AHEAD LIKE MYSELF, I THINK YOU CAN GET A BETTER JIST OF MY UNDERSTANDING THERE, ON PAGE 2.

Thanks

Dane
 

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  • #2
Could this in some ways be analogous to thinking of a direction field? Even though we know y to be a function of x while graphing the direction field of y'=f(x,y), we still graph lineal elements, which seems analogous to graphing in the z direction. Does f being continuous in, or on the rectangle insinuate that the direction field exist in that rectangle?
 
  • #3
Also, any critique of the paper is certainly welcome, before I submit it I will have it reviewed to make sure all is well.

Thanks

Dane

PS, pretty hard to understand for a mining engineering major, lol
 

FAQ: Calc 4 Student, Please help me understand Existance and Uniqueness

What is meant by "existence" in Calculus 4?

In Calculus 4, "existence" refers to the concept of whether a solution to a given problem or equation exists. In other words, can we find a value or set of values that satisfies the equation or problem?

How is "existence" related to "uniqueness" in Calculus 4?

"Uniqueness" in Calculus 4 refers to whether there is only one solution to a given problem or equation. If a solution exists and it is the only possible solution, then the problem is said to have both existence and uniqueness. However, if there are multiple solutions or no solutions, then the problem does not have uniqueness.

What types of equations or problems require consideration of existence and uniqueness in Calculus 4?

In Calculus 4, problems that involve differential equations, boundary value problems, and initial value problems often require consideration of both existence and uniqueness. These problems involve finding a solution that satisfies certain conditions or constraints, making it important to determine if a solution exists and if it is unique.

How do you determine if a solution exists in Calculus 4?

To determine if a solution exists in Calculus 4, you can use various techniques such as the method of separation of variables, the method of undetermined coefficients, or the method of variation of parameters. These methods involve solving the given equation or problem and checking if the solution satisfies the given conditions or constraints.

What happens if a solution does not exist or is not unique in Calculus 4?

If a solution does not exist or is not unique in Calculus 4, it means that the given problem or equation does not have a valid solution. This can occur if the problem is ill-posed or if the given conditions or constraints are not consistent. In such cases, further analysis or reevaluation of the problem may be necessary.

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