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orangeincup
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Homework Statement
Si atoms get doped inside GaAs to a concentration of 1.5*10^8 . Assume that the silicon atoms are
fully ionized and that 35percent atoms replace gallium and that 65% of the added
atoms replace arsenic t=300k
Fnd the acceptor and donor concentrations
Calculate electron / hole concentrations and Ef-Efi
Homework Equations
(Nd-Na)/2 + sqrt((Nd-Na/2)^2+ni^2)
(Na-Nd)/2 + sqrt((Na-Nd/2)^2+ni^2)
The Attempt at a Solution
Nd=.35*(7*10^15) =2.4*10^15
Na=(.65)*(7*10^15)=4.5*10^15
For the next part(assuming the above is correct), should I use ni of the GaAs or Si for the next part? Or the given value of 1.5*10^8?
(2.4*10^15-4.5*10^15)/2 + sqrt((2.4*10^15-4.5*10^15/2)^2+1.5*10^8^2) =-8.99*10^14 = donor concentration
(-2.4*10^15+4.5*10^15)/2 + sqrt((-2.4*10^15+4.5*10^15/2)^2+1.5*10^8^2)=1.2*10^15 = acceptor concentration