- #1
nchin
- 172
- 0
Calculus III, find shortest distance, 3 dimension problem? check my answer please??
What is the shortest distance from the point P = (0, 1, 2) to the line given by l(t) = (1+t, 2-2t, 3+3t)?
use distance formula
d = sqrt ((x-0)^(2) + (y-1)^(2) + (z-2)^(2))
d^(2) = ((x)^(2) + (y-1)^(2) + (z-2)^(2))
substitute l(t) values
=((1+t)^(2) + (1-2t)^(2) + (1+3t)^(2))
simplify
l ' (t) = 2 + 2t + 8t - 4 +6 + 18t
= 2 + 2t + 8t - 4 + 6 + 18t
=28t + 4
4(1+7t) = 0
t = - 1/7What do i do after i find the t value?
What is the shortest distance from the point P = (0, 1, 2) to the line given by l(t) = (1+t, 2-2t, 3+3t)?
use distance formula
d = sqrt ((x-0)^(2) + (y-1)^(2) + (z-2)^(2))
d^(2) = ((x)^(2) + (y-1)^(2) + (z-2)^(2))
substitute l(t) values
=((1+t)^(2) + (1-2t)^(2) + (1+3t)^(2))
simplify
l ' (t) = 2 + 2t + 8t - 4 +6 + 18t
= 2 + 2t + 8t - 4 + 6 + 18t
=28t + 4
4(1+7t) = 0
t = - 1/7What do i do after i find the t value?
Last edited: