- #1
Nakalay
- 7
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Hi. I am curious about the following nuclear reaction:
[tex]\nu_{e} + ^{71}_{31}Ga \rightarrow ^{71}_{32}Ge + e^{-}[/tex].
Can anyone explain to me why this reaction has an energy threshold of approximatly 0.23 MeV? How does one calculate the minimum energy of the neutrino for this reaction to take place?
Thanks in advance.
[tex]\nu_{e} + ^{71}_{31}Ga \rightarrow ^{71}_{32}Ge + e^{-}[/tex].
Can anyone explain to me why this reaction has an energy threshold of approximatly 0.23 MeV? How does one calculate the minimum energy of the neutrino for this reaction to take place?
Thanks in advance.