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Rissj3
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Hi, I'm in lab in which we have to titrate 0.09M NaOH into 25mL of 0.1M HCl/HOAc mixture.
I need help on how to calculate the concentration of HCl and HOAc in the mixture.
0.09M NaOH
1st equivalence point = 14.3mL
2nd equivalence point = 26.9mL
Difference of two equivalence points, 14.3-26.9= 12.6mL
I'm thinking to solve this problem I would have to use the dilution formula, M1V1=M2V2
M (0.025L) = (0.09M)(0.0143L)
M = 0.05148M HCl
M (0.025L) = (0.09M)(0.0126L)
M = 0.04536M HOAc
Is this correct or am I completely off?
Any help would be appreciated.
Thanks
Homework Statement
I need help on how to calculate the concentration of HCl and HOAc in the mixture.
0.09M NaOH
1st equivalence point = 14.3mL
2nd equivalence point = 26.9mL
Difference of two equivalence points, 14.3-26.9= 12.6mL
Homework Equations
I'm thinking to solve this problem I would have to use the dilution formula, M1V1=M2V2
The Attempt at a Solution
M (0.025L) = (0.09M)(0.0143L)
M = 0.05148M HCl
M (0.025L) = (0.09M)(0.0126L)
M = 0.04536M HOAc
Is this correct or am I completely off?
Any help would be appreciated.
Thanks