Calculate Current in B-Field Loop @t=8s

In summary, a circular loop with radius a = 0.25 m and N = 17 turns is placed in a uniform magnetic field pointing in the -z direction. The strength of the field varies with time according to B(t) = 0.01 t^3 T/s^3 in the interval between t = 0 and 15 s. To calculate the current in the windings at t = 8 s, the B-field and resistance R are needed. The induced emf at t = 8 s is 6.408849013 V and the resistance is 2.937389131 Ohms. Using the equation d(0.1963495408t^3)/dt = 2.937
  • #1
choey
2
0
A circular loop with radius a = 0.25 m and N = 17 turns lies in the plane of the page (x-y plane). The wire used in constructing the loop has a resistance per unit length of dR/dl = 0.11 W/m.

A spatially uniform magnetic field points in the -z direction (into the page). In the interval between t = 0 and 15 s, the strength of this field varies according to the expression B(t) = 0.01 t^3 T/s3.

Calculate the current in the windings at t = 8 s. (Give the magnitude and algebraic sign - let a current that is clockwise in the view shown in the figure defined to be positive.)

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First, I calculated the B-field @ t=8, which turned out to be 6.408849013 V.
Now, to find the current, I'm advised to write the equivalent Kirchoff's loop equation. I'm having a hard time doing this, because I'm given dR/dI, instead of just R. Since it's "resistance per unit length", I multiplied by 2pi*RN. What happens then?
 
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  • #2
What is the general expression for finding out induced emf wrt flux change ?
What is the value of induced emf at t = 8sec

Multiplying by 2pi*r*N would give you total resistance R.
Now you have induced emf and resistance. How will you find the current ?

Arun
 
  • #3
Huh. I swear I tried that to find R and therefore I. But this time it worked, actually. :)

Now I'm asked, "In the time interval between 0 and 15 s, how much electrical charge passes any given point in the windings? (Give magnitude only.)"

I have...
emf @ t=8 : dPhi/dt = 6.408849013 V
I @ t=8 : dQ/dt = -2.181818 A
R = 2.937389131 Ohms

Q = -2.181818t, right?
So, Q(15) - Q(0) = -2.181818 * 15 = 32.72727 C, but that was too easy and wrong. Where should I be headed?

EDIT:

I also tried this:
Since I know that Phi = BA = 0.01t^3 * 2pi * 0.25^2 * 17 (the # of windings) = 0.0333794219t^3
Then I have this equation:
d(0.1963495408t^3)/dt = 2.937389131 * dQ/dt.
I integrate both sides w/ respect to t, and I get
0.1963495408t^3 = 2.937389131*Q(t)
Then Q(t) = 0.0668449198t^3
Evaluating Q(t) for t=0..15, I get
0.0668449198(15)^3 = 225.6016042 C, which is still wrong.

EDIT:

I got it :)
 
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FAQ: Calculate Current in B-Field Loop @t=8s

How do you calculate the current in a B-field loop at t=8s?

To calculate the current in a B-field loop at t=8s, you will need to use the formula I = Q/t, where I is the current in amperes, Q is the charge in coulombs, and t is the time in seconds. You will also need to know the strength of the magnetic field and the area of the loop.

What is the significance of calculating the current in a B-field loop at t=8s?

Calculating the current in a B-field loop at t=8s can provide valuable information about the behavior and properties of the loop. It can help determine the strength of the magnetic field, the charge of the particles in the loop, and the direction of the current.

What factors can affect the accuracy of the current calculation in a B-field loop at t=8s?

There are several factors that can affect the accuracy of the current calculation in a B-field loop at t=8s. These include errors in measuring the magnetic field strength and loop area, as well as uncertainties in the charge and time measurements.

How does the current in a B-field loop change over time?

The current in a B-field loop can change over time due to various factors such as changes in the magnetic field strength, the number of charges in the loop, and the resistance of the loop. It may also change direction depending on the orientation of the loop and the direction of the magnetic field.

Can the current in a B-field loop at t=8s be negative?

Yes, the current in a B-field loop at t=8s can be negative. This indicates that the direction of the current is opposite to the direction of the magnetic field. It can also mean that the charges in the loop are moving in the opposite direction to the flow of current.

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