faisal said:i DONT understand this example given to me
q.1 A 9v battery with an internal resisrance of 0.1 ohms is connected to a 3 ohm resistance. What current flows across the circuit and what is the P.D. across the terminals of the battery
E=I(R+r)
I=E/(R+r)
answer 2.9A (i understand this part)
PD across battery= VR= (9-.29)=8.7V where on Earth did 0.29 come from?
faisal said:I Still don't understand here's my answer
a)2/9.5=0.2 amps
b)0.2X 9.5= 1.9v (V=IR)
To calculate the current, we can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or I = V/R. In this case, we would divide 4.5V by 12Ω to get a current of 0.375 amps.
Yes, there are other equations that can be used to calculate current and resistance, such as the power equation P = VI, where power (P) is equal to voltage (V) multiplied by current (I). However, Ohm's Law is the most commonly used equation for these calculations.
Voltage is typically measured in volts (V), while resistance is measured in ohms (Ω). It is important to use consistent units when using Ohm's Law to calculate current.
Knowing the current and resistance can help us understand how much power is being used and how much heat is being generated in a circuit. This information is crucial for designing and troubleshooting electronic devices.
Yes, there is a limit to the current that can flow through a battery and resistor. This limit is determined by the maximum voltage and resistance values, as well as the capacity of the battery. Exceeding this limit can cause damage to the components or even lead to a fire.