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A hollow brass tube (diameter = 3.23 cm) is sealed at one end and loaded with lead shot to give a total mass of 0.219 kg. When the tube is floated in pure water, what is the depth, z, of its bottom end?
through manipulation of some laws i have broken it down to this stage:
z = m/(πr2ρ)
where:
m=0.219 kg
r=0.0323/2=0.01615m
p=1000 kg/m^3
thus i have :
z= 0.219/ n(0.01615)2(1000)
but what the hell is n... i know its not the incidencs for water because nothing is getting reflected and i just tried to plug it into see what would happen and it doesn't work any help?
through manipulation of some laws i have broken it down to this stage:
z = m/(πr2ρ)
where:
m=0.219 kg
r=0.0323/2=0.01615m
p=1000 kg/m^3
thus i have :
z= 0.219/ n(0.01615)2(1000)
but what the hell is n... i know its not the incidencs for water because nothing is getting reflected and i just tried to plug it into see what would happen and it doesn't work any help?