Calculate Diameter of Larger Piston Given 500N Force & 10cm^2 Area

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To calculate the diameter of the larger piston in a hydraulic lift system, apply the principle of hydraulic pressure, which states that pressure is constant throughout the fluid. Given a force of 500 N on the smaller piston with an area of 10 cm², use the equation F_1/A_1 = F_2/A_2 to find the area of the larger piston. Once the area of the larger piston is determined, convert it to radius using A = πr², and then calculate the diameter with r = d/2. The problem emphasizes understanding the relationships between force, area, and pressure in hydraulic systems. This approach allows for an accurate determination of the larger piston’s diameter.
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Homework Statement


A hydraulic lift raises a 3000 kg car when 500 N force is applied to the smaller piston. If the smaller piston has an area of 10 〖cm〗^2, what is the diameter of the larger piston?


Homework Equations


p_1=p_2
F_1/A_1 =F_2/A_2
A_2=(F_2 A_1)/F_2
A=πr^2
r=d/2



The Attempt at a Solution


monkey/lightbulb=me from here
 
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Do you know what all of your relevant equations mean? You have more than enough to solve the problem. Specifically, look at F_1/A_1 =F_2/A_2. Let's say that A_2 is the area of the smaller piston, 10 cm^2. You're trying to find A_1, because after that, you can easily get the diameter. What's F_2, the force on the smaller piston? How about F_1, the force on the larger piston?
 
The basic rule for this type of question is that pressure is constant at the same level. I think if the height of water level is the same, then it is fairly straight forward.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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