Calculate Dielectric Thickness for 100pF Capacitor

[Kev1n]

1.
A capacitor is formed by 2 parallel plates separated by a dielectric of relative permattivity er = 12, the capacitor plates are 5mm x 10mm. Calculate the thickness of the dielectric required to create a capacitor of 100pF



2. C = eA / d therefore d=eA/C, we have C 100 x 10-9, area of pates 5x10-3 x 10x10-3 = 50x10-3mm2 (0.05m2



3. C = eA / D = 12 x 0.05 / 100 x 10-9
= 6000000
This is a massive figure so I am guessing incorrect any pointers

 

[Kev1n]

1.
A capacitor is formed by 2 parallel plates separated by a dielectric of relative permattivity er = 12, the capacitor plates are 5mm x 10mm. Calculate the thickness of the dielectric required to create a capacitor of 100pF



2. C = eA / d therefore d=eA/C, we have C 100 x 10-9, area of pates 5x10-3 x 10x10-3 = 50x10-3mm2 (0.05m2



3. C = eA / D = 12 x 0.05 / 100 x 10-9
= 6000000
This is a massive figure so I am guessing incorrect any pointers

Should I have used d = Eo x Er x A / C

12 x 8.85x10-12 x 50 x 10-3 / 100 x 10-9 = 5.31x10-5 = 0.0513mm

 

[kerimek]

?


I would like to clarify that the calculations provided in the content are correct. However, the result of 6000000 is in units of meters, which may seem like a large number. To convert this to a more practical unit, we can use the fact that 1 meter is equal to 1000 millimeters (mm). Therefore, the dielectric thickness required for a 100pF capacitor would be 6000000 mm, which is equivalent to 6000 meters (m). This may seem like a large thickness, but it is important to note that the relative permittivity of the dielectric material (er = 12) greatly affects the capacitance value. In comparison, a capacitor with the same dimensions but a vacuum as the dielectric material would only require a thickness of 0.0000083 m or 8.3 micrometers (μm) to achieve a capacitance of 100pF. This highlights the importance of choosing the appropriate dielectric material for a desired capacitance value.