Calculate Fill Rate for 183 US Gallon Bottle

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To calculate the fill time for a 183 U.S. gallon bottle filled at a rate of 1.7 grams per minute, first convert the bottle's volume to cubic meters, resulting in approximately 0.6927 m³. Given that water has a density of 1000 kg/m³, the mass of water in the bottle is about 692.7 kg, or 692,700 grams. Using the fill rate of 1.7 grams per minute, determine the total time required to fill the bottle by dividing the total mass by the fill rate. This calculation will yield the time in minutes, which can then be converted to years for the final answer. Understanding these conversions and calculations is essential for solving the problem accurately.
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Homework Statement


A bottle with a volume of 183 U. S. fluid gallons is filled at the rate of 1.7 g/min. (Water has a density of 1000 kg/m3, and 1 U.S. fluid gallon = 231 in.3.) In years, how long does the filling take?


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The Attempt at a Solution


Volume -> 42273 Units in.^3 -> 692730.3565 Units cm^3 -> .6927303565 Units m^3

But after this finding the mass of water and the fill rate I get messed up. I know is just simple conversion but I'm messing something up down the line.
 
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Well first, I can't really follow your work and only have trusty windows calculator if I wanted to, so I'll just say...

Actually yes I can, I see, you figured out how many cubic meters 183 gallons is, right?

mmk

If water has a density of 1000 kg/m^3, that's saying a m^3 of water has a mass of 1000 kg. You want to find out how much mass is in .6927 m^3. Can you do that? That's just a simple conversion or ratio or whatever you want to call it. So you need x g of water(you find x)

Then you know you have 1.7g/min, so convert that to xg/zyears, and you're looking for z, if there's 1.7 grams every minute, how many years are there for every x grams?

Here's a fun thing google calculator does
http://www.google.com/search?hl=en&rls=com.microsoft:en-US&q=183+gallons+to+m^3

but remember you won't have it on a test, so just use it to check your answers confidently
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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