Calculate frequency change due to gravity

In summary, the conversation discusses the frequency change of a radio signal transmitted from geosynchronous orbit due to non-constant gravity. The equations used to calculate the frequency shift include the universal gravitational constant and the Schwarzschild radius for Earth. The final result is a small blue shift, indicating a slightly higher frequency. There is also a link provided for further information on the gravitational redshift phenomenon.
  • #1
fyziksdunce
3
0
I'm trying to solve the frequency change due to gravity of a radio signal transmitted at 2x10^9 Hz from geosynchronous orbit (H = 35780 km). This (would be) easy if I could use the value g = 9.8m/s^2, the catch is "do not assume constant g".

The equation assuming constant g is:

(f_rec - f_trans)/f_rec = gH/c^2 (Eq 1)

(Note this is the form derived from the original energy conservation relation: hf = hf' + mgH, use m=E/c^2=hf/c^2).

My initial stab at it was to substitute an expression using the universal gravitational constant:

(f_rec - f_trans)/f_rec = (GM)*(1/r_earth - 1/(r_earth + H))/(c^2) (Eq 2)

where M is the mass of the Earth and G is the universal gravitational constant. This results in a frequency shift of ~+1 Hz (so small I needed to use a num2str command in MATLAB to see it given the magnitude of f_trans).

I then thought perhaps I was being cute with assuming H and an inverse distance would cancel w/o deleterious effects, so I went back to the unsimplified form:

(f_rec - f_trans)/f_rec = (GMH)*(1/r_earth - 1/(r_earth + H))^2/(c^2) (Eq 3)

This yielded a frequency shift of ~+5 Hz (again so small I needed to use a num2str command in MATLAB to see it given the magnitude of f_trans).

My issue is that I'm not sure I'm accounting for non-constant gravity correctly; if I am then I've solved the problem, if not...

Please forgive if this is an easy problem or there is a "well-known" treatment for non-constant gravity I am just not finding, I am a mathematician with only a high school physics background taking a masters level physics class.

Thanks for the help.
 
Physics news on Phys.org
  • #2
See link below.

According to that, the red shift should be
Δf/f = 1/{sqrt(1 - rs/R1) - 1/sqrt(1 - rs/R2)}

where rs is the Schwarzschild radius for Earth = 2GM/c^2, M = mass of Earth, or about 9 mm; R1 is the distance from Earth center to the satellite, and R2 is the radius of Earth.
Since Δf/f < 0 this amounts to a blue shift, as you also found. So Δf/f is actually > 0.

http://en.wikipedia.org/wiki/Gravitational_redshift
 

FAQ: Calculate frequency change due to gravity

What is the formula for calculating frequency change due to gravity?

The formula for calculating frequency change due to gravity is Δf = (f₀ * g * h) / c², where Δf is the change in frequency, f₀ is the initial frequency, g is the acceleration due to gravity, h is the height difference, and c is the speed of light.

How does gravity affect the frequency of light?

Gravity affects the frequency of light by causing it to shift towards the red end of the spectrum when an object emitting the light is in a strong gravitational field, such as near a black hole. This shift is known as gravitational redshift and is a result of the light losing energy as it moves against the pull of gravity.

What units are used to measure frequency change due to gravity?

The units used to measure frequency change due to gravity are hertz (Hz). This is the standard unit for measuring frequency, which represents the number of cycles per second.

Can frequency change due to gravity be observed on Earth?

Yes, frequency change due to gravity can be observed on Earth. This phenomenon is known as the gravitational redshift and has been observed in experiments measuring the frequency of light in different gravitational fields.

What other factors can affect frequency change due to gravity?

Other factors that can affect frequency change due to gravity include the mass and density of the object causing the gravitational field, as well as the distance between the object and the observer. These factors can all impact the strength of the gravitational field and therefore the amount of frequency change experienced by the light.

Back
Top