Calculate Heat of Fusion of Ice

[ZiJem]

Calculate heat of fusion.?
find the heat of fusion of ice using the ffg. data obtained from an experiment:

wt. of brass calorimeter = 50 g
specific heat of brass calorimeter = 0.09 cal/g-°C
m of ice= 20.45 g at 0°C
TF= 20 °C
mH2O = 200 g at 30°C

 

[Borek]

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methods

 

[quicknote]

The heat of fusion of ice can be calculated using the following formula:

Q = m x c x ΔT

Where:
Q = heat energy (cal)
m = mass (g)
c = specific heat (cal/g-°C)
ΔT = change in temperature (°C)

First, we need to calculate the heat energy gained by the water when it cools down from 30°C to 20°C. This can be done using the formula:

Q = m x c x ΔT
= 200g x 1 cal/g-°C x (30°C - 20°C)
= 2000 cal

Next, we need to calculate the heat energy lost by the brass calorimeter when it heats up from 20°C to 30°C. This can be done using the formula:

Q = m x c x ΔT
= 50g x 0.09 cal/g-°C x (30°C - 20°C)
= 45 cal

Since the heat energy lost by the calorimeter is equal to the heat energy gained by the water, we can set up the following equation:

2000 cal = m x 1 cal/g-°C x ΔT

Solving for m, we get:

m = 2000 cal / (1 cal/g-°C x 10°C)
= 200 g

Therefore, the mass of ice that melted is 200 g.

Now, we can calculate the heat of fusion using the formula:

Q = m x Lf

Where:
Q = heat energy (cal)
m = mass (g)
Lf = heat of fusion (cal/g)

Substituting the values, we get:

2000 cal = 200 g x Lf

Solving for Lf, we get:

Lf = 2000 cal / 200 g
= 10 cal/g

Therefore, the heat of fusion of ice is 10 cal/g.