Calculate Horizontal Ball Drop at 41.3m/s Velocity

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To calculate the drop of a ball thrown horizontally at 41.3 m/s over a distance of 17.0 m, the time of flight must first be determined. The horizontal velocity (Vox) is 41.3 m/s, and since there is no horizontal acceleration (ax = 0), the time (t) can be calculated using the formula t = distance / velocity, resulting in t = 17.0 m / 41.3 m/s. The vertical drop can then be calculated using the formula for vertical motion, y = 0.5 * g * t^2, where g is 9.8 m/s². Substituting the calculated time into this formula will yield the total drop of the ball by the time it reaches the catcher. The final calculation provides the necessary information on how far the ball will drop during its flight.
pookisantoki
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A Major league pitcher can throw a ball in excess of 41.3m/s. If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is 17.0m away from the point of release?
So Ay=-9.8
X=17m
t=?
Vox=0
V=41.3
y=(Vy^2-Voy^2)2g
I thoguht i would use this formula but wasnt sure how to figure Voy out since Vy=0...
Please help!
 
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pookisantoki said:
X=17m
t=?
Vox=0

Vox, the initial horizontal speed, is not 0, it is ____?
Also, ax = ____?

Can you fill in the blanks, and then use this information to find t?
 

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