- #1
aruhland
- 2
- 0
- Homework Statement
- For the reaction below, constant pressure heat of reaction is Qp=-2051 kj/mol at 25 C. What is the constant volume heat of reaction, Qv, at 25 C?
10CO(g) + 21H2(g) --> C10H22(l) + 10 H2O(l)
- Relevant Equations
- enthalpy change=internal energy change + change in mol=*R*T
internal energy change=Qv-Pext*volume change
Qp=deltaH
Qv=deltaU
deltaH=deltaU + deltanRT
Qv=deltaH - deltanRT
=-2051 kj/mol - (11mol-31mol)(8.3145x10-3J/Kmol)(298.15K)
=-2001.42 kJ/mol
I thought I did this correctly but it comes up as wrong for my online assignment. Any suggestions?
deltaH=enthalpy change
deltaU=internal energy change
Qv=deltaU
deltaH=deltaU + deltanRT
Qv=deltaH - deltanRT
=-2051 kj/mol - (11mol-31mol)(8.3145x10-3J/Kmol)(298.15K)
=-2001.42 kJ/mol
I thought I did this correctly but it comes up as wrong for my online assignment. Any suggestions?
deltaH=enthalpy change
deltaU=internal energy change